Some measures are given in the adjacent figure, find the area of

In the given fig. ABD is right angled triangle at A,

Given that AB = 40cm, and AD = 9cm

Therefore, the area of triangle ABD

= 180 sqm

Now, the area of triangle, ∆BCD

Now area of quadrilateral ABCD,

= 180 + 390

= 570 sq m