In a circle with centre P, chord AB is drawn of length 13 cm, seg PQ ⊥ chord AB, then find l(QB).

We know that,
The perpendicular from the centre of a circle to a chord bisects the chord.
Therefore, it is given that,
AB=13 cm
PQ perpendicular to AB
|(QB) = AB/2
| (QB) = 13/2
| (QB) = 6.5 cm
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