Q7 of 14 Page 119

The length of a chord of a circle of 16.8 cm, the radius is 9.1 cm. Find its distance from the centre.


Length of the chord = 16.8 cm


Radius = 9.1 cm


Let the distance from the centre of the chord be d.


Perpendicular drawn from the centre of the circle to the chord bisects the chord.


So, AC = CB = = 8.4cm.


In AOC,


Applying Pythagoras theorem we have


OC2 + AC2 = AO2


d2 + 8.42 = 9.12


d2 = 82.81 – 70.56


(d = 3.5cm)


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