Q8 D of 126 Page 129

Solve for x:


To find: value of x


Formula Used:


Given:


LHS = cos(2sin-1 x)


Let θ = sin-1 x


So, x = sin θ … (1)


LHS = cos(2θ)


= 1 – 2sin2 θ


Substituting in the given equation,





Substituting in (1),




Therefore, are the required values of x.


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