If f : R → R, g : R → R are given by f(x) = (x + 1)² and g(x) = x² + 1, then write the value of fog (–3).

Formula:-

(I)Let f : AB and g : BC be two functions.

Then, the composition of f andg, denoted by g o f, is defined as the function g o f : AC

given by g o f (x) = g (f (x))

Given:-

(i) f : R → R

(ii) g : R → R

(iii) f(x) = (x + 1)²

(iv) g(x) = x² + 1

fog(-3)=f(g(-3))

fog(-3)=f((-3)²+1)

fog(-3)=f(10)

fog(-3)=(10+1)²

fog(-3)=121