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14. Differentials, Errors and Approximations
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Q7 of 61 Page 14

Mark the correct alternative in the following:

A sphere of radius 100 mm shrinks to radius 98 mm, then the approximate decrease in its volume is


we know that volume of sphere = v = (4/3)×πr3 (r is radius of sphere)

r = 100mm



=4πr2Δr


Δr = (98-100)


=-2


Δv=4π(100)2×(-2)


Δv = - 80,000π mm3ans

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Questions · 61
14. Differentials, Errors and Approximations
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