If A + B + C = π, prove that
sin2 A – sin2 B + sin2 C = 2sin A cos B sin C
= sin2 A – sin2 B + sin2 C
Using formula ,
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Using ,
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since A + B + C = π
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And sin(π – A) = sinA
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Using , cos2A = 1 – 2sin2A
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= 2sinAcosBsinC
= R.H.S
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