Q9 of 76 Page 2

Mark the correct alternative in the following:

R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x− 3. Then, R−1 is


Since, y = x – 3;

Therefore, for x = 11, y = 8.


For x = 12, y = 9.[ But the value y = 9 does not exist in the given set.]


For x = 13, y =10.


So, we have R = {(11, 8), (13, 10)}


Now, R−1 = {(8, 11), (10, 13)}.


Therefore, option A is correct.

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