Find the particular solution of the different equation.2xy + y2 - 2x2
= 0, it being given that y = 2 when x = 1
2xy + y2 - 2x2
= 0
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⇒ the given differential equation is a homogenous equation.
The solution of the given differential equation is :
Put y = vx
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Integrating both the sides we get:
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Resubstituting the value of y = vx we get
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Now,
y = 2 when x = 1
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