For any positive real number x, find the value of ![]()
x(a – b) (a + b) × x(b – c) (b + c) × x(c – a) (c + a)
= xa.a - b.b × xb.b – c.c × xc.c – a.a
= xa.a – b.b + b.b – c.c + c.c – a.a
= xo = 1
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