Q1 of 4 Page 210

Let's draw a triangle whose two angles are of measurements 45° and 30° and length of the opposite side of 30° angle is 6 cm. Now I construct the above triangle and write down the steps of construction and prove it logically.

Given: 1st angle = 45° and 2nd angle = 30°

and the side opposite of 30° angle is of 6cm


Steps of Construction:


Step 1:


Draw a line using the scale AB.



Step 2:


At A, draw an angle of 90° using compass and scale by standard procedure and then bisect the angle at 45°



Step 3:


Now, again take a compass keep the needle on point B and draw an angle of 30°.



Step 4:


Take distance 6cm in compass keep the needle of the compass on point A and mark an arc intersecting ray drawn in step 2. Mark the intersection point as C and join BC



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If I draw a triangle length of whose two sides are 5 cm and 4 cm and the measurement of the angle opposite to the side of length 4 cm is 45°, then let's see what type of triangle I shall get. It is seen that it is not possible to draw any triangle with these conditions.

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Let’s draw a triangle whose two sides are 6cm and 7cm and the measurement of the angle opposite to the side of length 7cm. is 60°. Let’s write what will the measurement of the sides to form a triangle.

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Let’s construct a triangle whose length of two sides are 6cm. and 9cm. and the measurement of the angle opposite to the side of length 9cm. is 105°. Let’s write for what length of sides we will not be able to construct two triangle.