Obtain the expression for the ratio of the de-Broglie wavelengths associated with the electron orbiting in the second and third excited states of hydrogen atom.
As de Broglie suggested that the wavelength of a matter is associated with its momentum as ![]()
Where P is the momentum of matter (mv)
And h is Planck’s constant i.e. ![]()
The velocity of an electron following Bohr model is given by
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Where Z is the atomic number of hydrogen-like species
And n is the orbit in which the electron is revolving
Speed of electron in 2nd excited state will be
As Z = 1
And n =3
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So, momentum in a 2nd excited state will be
P= mv
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Therefore then, ![]()
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Now for 3rd excited state
Speed of electron in a 3rd excited state will be
As Z = 1
And n =4
![]()
So, momentum in a 3rd excited state will be
P= mv
![]()
![]()
So,

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