If triangle ∠PQR = ∠PRQ. If we extend QR on both sides, then two exterior angles are formed. Let’s prove that the measurement of external angles are equal.
Let us first construct diagram for the above proof:

QR is extended on both the sides.
In the figure, ∠PQS and ∠PRT are the two exterior angles.
It is given that ∠PQR = ∠PRQ which means that the given triangle is an isosceles triangle.
Hence length PQ = PR.
Now ∠PQS + ∠PQR = 180° ……(i) [as they form linear pair that angles in straight line always add up to 180°]
Similarly, ∠PRQ + ∠PRT = 180° ……. (ii).
For the equations (i) and (ii), the right-hand side is equal which means that the left-hand side should also be equal.
∠PQS + ∠PQR = ∠PRQ + ∠PRT
∠PQS and ∠PRQ gets eliminated as they both are equal angles.
So, we can state that ∠PQS = ∠PRT.
Hence it is proved that the measurement of external angles is equal.
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