Apply the first law of thermodynamics to a resistor carrying a current i. Identify which of the quantities ΔQ, ΔU and ΔW are zero, which are positive and which are negative.
First law of thermodynamics states –
the total energy of an isolated system is constant, energy can neither created nor destroyed, but can be transformed from one form to another
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where
ΔU is the change in the internal energy,
∆Q is the heat added to the system,
and ∆W is the work done by the system.
Now, here the battery is doing positive work on a resistor carrying current i.
Thus, ∆W is positive.
The work done on the resistor is used to increase its thermal energy in the form of heat, thus ∆Q is positive.
As the temperature of the resistor rises, ΔU is positive.
Couldn't generate an explanation.
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