Prove that
is an irrational number.
If possible, let
be a rational number equal to x. Then,
x = ![]()
x2 = (
)2
= (
)2 + (
)2 + 2 *
* ![]()
= 3 + 5 + 2![]()
= 8 + 2![]()
x2 – 8 = 2![]()
= ![]()
Now, x is rational
x2 is rational
is rational
is rational
But,
is irrational
Thus, we arrive at a contradiction. So, our supposition that
+
is rational is wrong.
Hence,
+
is an irrational number.
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