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41. Electric Current through Gases
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Q20 of 49 Page 352

The plate current in a triode can be written as

Show that the mutual conductance is proportional to the cube root of the plate current.


Given:



gm is the mutual conductance, ip is the plate current, Vp is the plate current and Vg is the grid voltage.



Taking cube on both sides,



hence proved


More from this chapter

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18

The plate resistance and the amplification factor of a triode are 10 kΩ and 20. The tube is operated at plate voltage 250 V and grid voltage –7.5 V. The plate current is 10 mA

(a) To what value should the grid voltage be changed so as to increase the plate current to 15 mA?


(b) To what value should the plate voltage be changed to take the plate current back to 10 mA?


19

The plate current, plate voltage and grid voltage of a 6F6 triode tube are related as

Ip = 41(Vp + 7 Vg) 1.41, Where Vp and Vg are in volts and ip in microamperes. The tube is operated at Vp = 250 V, Vg = –20 V. Calculate


(a) the tube current,


(b) the plate resistance,


(c) the mutual conductance and


(d) the amplification factor.


21

A triode has mutual conductance = 2.0 millimho and plate resistance = 20 kΩ. It is desired to amplify a signal by a factor of 30. What load resistance should be added in the circuit?

22

The gain factor of an amplifier is increased from 10 to 12 as the load resistance is changed from 4 kΩ to 8 KΩ. Calculate (a) the amplification factor and (b) the plate resistance.

Questions · 49
41. Electric Current through Gases
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