Let
, then show that A2 – 4A + 7I = O.
Using this result calculate A3 also.
OR
If
, find A-1 , using elementary row operations.
Given: ![]()
To show: A2 – 4A + 7I = O and also find A3
Proof:
Firstly, we calculate A2
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Putting the value in given equation, we get
A2 – 4A + 7I
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= 0
= RHS
Now, we have to find the A3
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OR
Given: 
We know that, A = IA

R2→ R2 – 2R1


R3→ 3R3


R3→ R3 – R2


R1→ R1 – R3


R2→ R2 + 7R3


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R3↔ R2

R2→ -R2


This is similar to
I = A-1A
Hence, 
Couldn't generate an explanation.
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