(a-b)³+(b-c)³+ (c-a)³=

15

If a+b+ c =9 and ab + bc + ca = 23, then a²+b² + c²=

16

If a+b+ c =9, then ab+bc+ca=23, then a³+b³ + c³ – 3abc =

18

=

19

The product (a+b) (a-b) (a²-ab+b²) (a²+ab+b²) is equal to