In nature, the failure of structural members usually result from large torque because of twisting or bending rather than due to tensile or compressive strains. This process of structural breakdown is called buckling and in cases of tall cylindrical structures like trees, the torque is caused by its own weight bending the structure. Thus the vertical through the centre of gravity does not fall within the base. The elastic torque caused because of this bending about the central axis of the tree is given by
. Y is the Young’s modulus, r is the radius of the trunk and R is the radius of curvature of the bent surface along the height of the tree containing the centre of gravity (the neutral surface). Estimate the critical height of a tree for a given radius of the trunk.
Let us assume that Tree is uniform, and considering tree is just about to fall.
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Let the distance from ground = h/2
Radius of curvature =R
Radius of Tree=r
When Tree will, one part of radius will remain but other will be different.

Using Properties of Triangle we can write,
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And we know that d<<R, therefore its square will be less compared, hence neglecting d2, we can write,
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It is given in questions elastic torque is given by
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It will be equal to,
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