Q2 of 27 Page 77

A uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly

As we know moment of inertia of a rod about its perpendicular bisector is so from this formula we can say easily that if L increases then I also increases, so on heating a uniform metallic rod its length will increase so moment of inertia of rod increased from I1 to I2 an obviously I2 > I1 or .

Now also we will apply conservation of angular momentum i.e.


I1ω1= I2ω2 or so from here ω1>ω2 which means angular speed decreases.


Therefore option (b) is correct.

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