Q37 of 37 Page 1

Derive mirror equation for a convex mirror. Using it, show that a convex mirror always produces a virtual image, independent of the location of object.

OR


(a) Draw a ray diagram for final image formed at distance of distinct vision (D) by a compound microscope and write expression for its magnifying power.


b) An angular magnification (magnifying power) of 30x is desired for a compound microscope using as objective of focal length 1.25cm and eye piece of focal length 5cm. How will you set up the compound microscope?


Let us consider the convex mirror of focal length = f

The object is placed on principle axis.


Distance between object and the mirror= u


The distance between the image and the mirror = v



Using the ray diagram








Similarly,



But DE=AB and when the aperture of the mirror is very small then EF= PF


Hence, equation (ii) becomes





By looking at the diagram, PF= f; PB1=v; PB = u, PC= 2f, therefore,







Dividing the above equation (4) by uvf, we get




For a convex mirror: focal length f is always positive


f >0


Since the object is on the left of the convex mirror, u<0



Using the above formula, we can conclude that v is positive if the image is at the back of the mirror. Therefore, the image is virtual whatever be the value of u.


OR


The magnification of the microscope is given by m= mome where, mo is the magnification due to objective lens and me is the magnification due to eyepiece of microscope.


Magnification of objective lens



Magnification of eyepiece




b) Given: angular magnification = 30


Focal length of eyepiece fe = 5cm


Focal length of objective fo = 1.25 cm


The image formed at least distance of vision= d= 25cm


Magnification of eyepiece me=



Magnification of objective mo = m/ me





Now using, lens makers formula,





Again, using lens maker’s formula for eyepiece,






The distance between object and eyepiece = 4.17 cm


Separation between the objective and eyepiece= 4.17+7.5 = 11.67 cm


More from this chapter

All 37 →
33

Show that can not spontaneously emit a proton.

Given: = 238.05079u, = 237.05121u, = 1.00783u


34

Suggest an idea to convert a full wave bridge rectifier to a half wave rectifier by changing the connecting wire/s. Draw the diagram and explain your answer.

35

(a) Using Gauss’s law, derive expression for intensity of electric field at any point near the infinitely long straight uniformly charged wire.

(b)The electric field components in the following figure are Ex = αx, Ey = 0, Ez= 0; in which α = 400 N/C m. Calculate (i) the electric flux through the cube, and (ii) the charge within the cube assume that a = 0.1m.



OR


(a) Define electrostatic potential at a point. Write its SI unit.


Three charges q1, q2 and q3 are kept respectively at points A, B and C as shown in figures. Write the expression for electrostatic potential energy of the system.


(b) Depict the equipotential surfaces due to


(i) an electric dipole


(ii) two identical negative charges separated by a small distance.


36

In the following diagram, the arm PQ of the rectangular conductor is moved from x= 0; outwards. The uniform magnetic field is perpendicular to the plane and extends from x = 0 to x = b and is zero for x >b. Only the arm PQ possesses substantial resistance ‘r’. Consider the situation when the arm PQ is pulled outwards from x = 0 to x = 2b, and is then moved back to x = 0 with constant speed ‘ѵ’. Obtain expressions for the (i) electric flux, (ii) the induced emf, (iii)the force necessary to pull the arm and (iv) the power dissipated as Joule heat. Sketch the variation of these quantities with distance.


OR


Write working principle of cyclotron and with a suitable diagram explain its working. Give any two applications of cyclotron.