The magnitude of projection of
on
is ___________
OR
Vector of magnitude 5 units and in the direction opposite to
is ___________
Given: Two vectors
and ![]()
To Find: Projection of
on ![]()
We know, projection of
on
is = ![]()
Similarly, The magnitude of projection of
on
is,

OR
Given: A vector
is given.
To Find: A vector opposite to the given vector of magnitude 5.
Let ![]()
So, ![]()
Therefore, the unit vector opposite to the vector
is,
![]()
So, the vector of magnitude 5 is,
![]()
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