Q24 of 26 Page 85

Before the neutrino hypothesis, the beta decay process was thought to be the transition,


If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.


The energy after decay produced proton and electron = 936 MeV and 2.078 MeV

Given


The beta decay process before establishment of neutrino hypothesis is given as



Hence, according to the beta decay process, the neutron is at rest before the decay starts.


Formula Used


Conservation of Energy law: The formula used before and after beta decay, the law of energy conservation tell us that the energy in an isolated system remain constant.



where


is the initial kinetic energy, is the final kinetic energy, is the initial potential energy and is the final potential energy


Explanation


When the neutron is at rest the momentum ( of the neutron is zero, but the energy () is


Before decay (neutron):


After decay (proton electron):



Energy of proton:


Energy of electron:


Using the law of energy conservation




Placing the values of , we get




With the effective momentum



We get the value of




Therefore, the energy after decay produced proton and electron is




More from this chapter

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22

Deuteron is a bound state of a neutron and a proton with a binding energy. A -ray of energy E is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the n and p move in the direction of the incident -ray. If E = B, show that this cannot happen. Hence calculate how much bigger than B must E be for such a process to happen.

23

The deuteron is bound by nuclear forces just as H-atom is made up of p and e bound by electrostatic forces. If we consider the force between neutron and proton in deuteron as given in the form of a Coulomb potential but with an effective charge e’:


Estimate the value of (e’/e) given that the binding energy of a deuteron is 2.2 MeV.


25

The activity R of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:

(i) Plot the graph of R versus t and calculate half-life from the graph.


(ii) Plot the graph of versus t and obtain the value of half-life from the graph.


26

Nuclei with magic no. of proton Z = 2, 8, 20, 28, 50, 52 and magic no. of neutrons N = 2, 8, 20, 28, 50, 82 and 126 are found to be very stable.

(i) Verify this by calculating the proton separation energy


Sp for 120Sn (Z = 50) and 121Sb = (Z = 51).


The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by


Sp = (MZ–1, N + MH – MZ,N) c2.


Given 119In = 118.9058u, 120Sn = 119.902199u,


121Sb = 120.903824u, 1H = 1.0078252u.


(ii) What does the existence of magic number indicate?