A person travelling by a car moving at 100 km h–1 finds that his wristwatch agrees with the clock on a tower A. By what amount will his wristwatch lag or lead the clock on another tower B, 1000 km (in the earth’s frame) from the tower A when the car reaches there?
Time taken by the car to reach the tower B from tower A =
.
As the frame of wrist watch is moving
the wrist watch will lag by ![]()
Where
, V is velocity of moving object and C is speed of light in vacuum i.e. ![]()
And
is time in rest frame .
V=![]()
as
using binomial expansion we know we can write
when ![]()
Similarly,
=![]()
![]()
![]()
And as we can see the calculated value is too small to make drastic affect that’s why we don’t face any trouble in real life situation.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.