Q8 of 50 Page 120

The CFSE for octahedral [CoCl6]4– is 18,000 cm–1. The CFSE for tetrahedral [CoCl4]2– will be

Crystal field splitting energy for tetrahedral is times that for octahedral


∆t= ∆o


∆t= ×18,000 cm–1=8,000 cm–1


Thus, Option C is the correct answer.

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