Q25 of 29 Page 26

An electron and a positron are released from (0, 0, 0) and (0, 0, 1.5R ) respectively, in a uniform magnetic field , each with an equal momentum of magnitude p = e BR. Under what conditions on the direction of momentum will the orbits be nonintersecting circles?


Because of electric charge the initial velocities are along –z for positron and +z for electron. Then it experiences Lorentz force and start rotation. The rotation is limited to the y-z plane as no involvement of any x directing components.


The momentum P is always perpendicular to the radius in circular motion.



Let us assume the momentum of the electron is Pelectron and the positron is Ppositron.


So, the coordinates of the center of their paths are going to be,


Ce = (0, Rsinθ, Rcosθ)


Cp = (0, -Rsinθ, 1.5R-Rcosθ)


The condition for the paths being non intersecting circles is that the distance between the centers is greater than 2R.


Distance between the center,


D2 = (Rsinθ - (-Rsinθ)2 + (Rcosθ - (1.5R – cosθ))2


= 4R2sin2θ + (2Rcosθ – 1.5R)2


= 4R2sin2θ + 4R2cos2θ – 6R2cosθ +2.25R � � �2


= 6.25R2 – 6R2cos2θ


From the condition; D2>4R2


6.25R2 – 6R2cos2θ > 4R2


2.25/6 > cosθ


cosθ < 0.375


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26

A uniform conducting wire of length 12a and resistance R is wound up as a current carrying coil in the shape of (i) an equilateral triangle of side a; (ii) a square of sides a and, (iii) a regular hexagon of sides a. The coil is connected to a voltage source V0. Find the magnetic moment of the coils in each case.

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Consider a circular current-carrying loop of radius R in the x-y plane with center at origin. Consider the line integral

taken along z-axis.


(a) Show that monotonically increases with L.


(b) Use an appropriate Amperian loop to show that .