Q8 of 26 Page 1

The wavelength λ of a photon and the de-Broglie wavelength of an electron have the same value. Show that energy of a photon is (2λmc/h) times the kinetic energy of electron; where m, c and h have their usual meaning.

Let λ be the wavelength of the photon. The wavelength of De-Broglie’s wavelength is given by,



Where, m = mass of electron


v = velocity


The kinetic energy of the electron is given by,





Photon has energy as,



Taking ration of kinetic energy and energy we get,




Thus, the energy of a photon is (2lmc/h) times the kinetic energy of electron.


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