The wavelength λ of a photon and the de-Broglie wavelength of an electron have the same value. Show that energy of a photon is (2λmc/h) times the kinetic energy of electron; where m, c and h have their usual meaning.
Let λ be the wavelength of the photon. The wavelength of De-Broglie’s wavelength is given by,
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Where, m = mass of electron
v = velocity
The kinetic energy of the electron is given by,
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Photon has energy as,
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Taking ration of kinetic energy and energy we get,

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Thus, the energy of a photon is (2lmc/h) times the kinetic energy of electron.
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