(a) An electric dipole of dipole moment
consists of point charges +q and –q separated by a distance 2a apart. Deduce the expression for the electric field
due to the dipole at a distance x from the centre of the dipole on its axial line in terms of the dipole moment
. Hence show that in the limit ![]()
(b) Given the electric field in the region
=
, find the net electric flux through the cube and the charge enclosed by it.
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(a) Electric field intensity at point P due to charge –q,
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Due to charge +q,
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Net electric field at point P,
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For![]()
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(b) Only the face perpendicular to the direction of r-axis, contribute to the electric flux. The remaining faces of the cube give zero contribution.

Total flux ![]()

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(charge enclosed) q=ϵoϕ=2a3ϵo
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