Two dice are thrown together once. Find the probability of getting a sum of more than 9.

When two dice are thrown, the possible outcomes are

{(1,1) (1,2) (1,3) (1,4) (1,5) (1,6), (2,1) (2,2) (2,3) (2,4) (2,5) (2,6), (3,1) (3,2) (3,3) (3,4) (3,5) (3,6), (4,1) (4,2) (4,3) (4,4) (4,5) (4,6), (5,1) (5,2) (5,3) (5,4) (5,5) (5,6), (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

The outcomes in which sum of no's is 9 are ={(3,6) (4,5) (5,4) (6,3)}

No of Total possible outcomes = 36

No of favourable outcomes = 4

and, Probability of an event

Therefore,

P(Getting sum 9)