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7. Factorization
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Q2 of 188 Page 7

Resolve each of the following quadratic trinomials into factors:

Here, coefficient of x2 = 2, coefficient of x = - 3 and constant term = -2

We shall now split up the coefficient of x i.e., -3 into two parts whose sum is -3 and product is 2 * -2 = - 4


So, we write middle term -3x as -4x + x


Thus, we have


2x2 - 3x – 2 = 2x2 - 4x + x – 2


= 2x (x – 2) + 1 (x – 2)


= (x – 2) (2x + 1)


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Questions · 188
7. Factorization
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