A bag contains 4 red, 5 black and 6 white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is:
(i) white
(i) red
(iii) not black
(iv) red or white
Here, n(S) = 15
(i) n(E) = 6
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(ii) n(E) = 4
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(iii) number of events of getting black balls, n(E) = 5
∴ probability of getting black balls, P(E) = ![]()
Hence, probability of getting black balls = 1 – P(E) = 1 – ![]()
(iv) number of events of getting a red or white ball, n(E) = 10
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