Q1 of 32 Page 25

A coin is tossed 1000 times with the following frequencies:

Head: 455, Tail: 545


Compute the probability for each event.

Given,


The coin tossed = 1000 times


The total number of trial = 1000


Lets assum,


The event of getting head = E


The event of getting tail = F


Then,


Number of trials in which the E happens = 455


So,


Probability of E =


P (E) =


Similarly,


The probability of the event getting a tail =


P (F) =


Note: we note that P(A)+P(B) = 0.48+0.52


Therefore, A and B are the only two opposite outcomes.


More from this chapter

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2

Two coind are tossed simultaneously 500 times with the following frequencies of different outcomes:

Two heads: 95 times


One tail: 290 times


No head: 115 times


Find the probability of occurrence of each of these events.

 3

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes :

















Outcome:



No head



One head



Two head



Three head



Frequency:



14



38



36



12



If the three coins are simultaneously tossed again, compute the probability of :


(i) 2 heads coming up.


(ii) 3 heads coming up.


(iii) at least one head coming up.


(iv) getting more heads than tails.


(v) getting more tails than heads.

 4

1500 families with 2 children were delected randomly and the following data were recorded:















No. of girls in a family :



0



1



2



No. of families :



211



814



475



If a family is chosen at random, compute the probability that it has:


(i) No girl


(ii) 1 girl


(iii) 2 girls


(iv) At most one girl


(v) More girls than boys.

 5

In a cricket match, a batsman hits a boundry 6 times out of 30 balls he plays.

Find the probability that on a ball played :


(i) he hits boundry


(ii) he does not hit a boundry.