Construct a ΔABC in which AB+AC=5.6 cm, BC=4.5 cm, and ∠B = 45°.

We are asked to construct a triangle ABC in whichAB+AC=5.6 cm, BC=4.5 cm, and ∠B = 45°, and We will follow the following algorithm for the construction

Steps of construction

STEP1: Draw BC of 4.5 cm.

STEP2: Draw∠B = 45°.

STEP3: From ray BE, cut BD of 5.6 cm.

STEP4: Draw segment DC.

STEP5: Draw the perpendicular bisector of DC, intersecting the ray BE at A

STEP6: Draw segment AC.

ABC is the required triangle.