Find the value of:
(i) ![]()
(ii)![]()
(iii) ![]()
(iv) ![]()
(v) ![]()
(i)
=
(Cancelling numerator and denominator with 5)
=
(Therefore,
= 4,
= 9)
(ii) ![]()
=
=
(Therefore,
= 21,
= 25)
(iii)
=
(Cancelling numerator and denominator with 3)
=
(Therefore,
= 23,
= 24)
(iv)![]()
=
× ![]()
We know that,
×
= ![]()
= 22 × 3 × 13
= 156
(v) ![]()
=
× ![]()
We know that,
×
= ![]()
= 5 × 9 × 2
= 90
Couldn't generate an explanation.
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