Q4 of 34 Page 189

If tan A = cot B, prove that A + B = 90°

tan A = cot (90°- A) = cot B

Therefore,

90° - A = B

A + B = 90°

Hence proved

More from this chapter

All 34 →
2

Show that:

(i) tan 48° tan 23° tan 42° tan 67° = 1

(ii) cos 38° Cos 52° – sin 38° sin 52° = 0

 3

If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A

 5

If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A

 6

If A, B and C are interior angles of a triangle ABC, then show that