A and B can finish a work in 20 days. A alone can do
th of the work in 12 days. In how many days can B alone do it?
Given,
A and B can finish a work in = 20 days
A can
work in = 12 days
∴ A+ B ‘s 1 day work = ![]()
∴ A’s 1 day work = ![]()
B’s 1 day work = (A+B)’s 1 day work – A’s 1 day work
= ![]()
Thus B can finish the work in = ![]()
Couldn't generate an explanation.
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