An element is placed in 2nd Group and 3rd Period of the Periodic Table, burns in presence of oxygen to form a basic oxide.
(a) Identify the element.
(b) Write the electronic configuration.
(c) Write the balanced equation when it burns in the presence of air.
(d) Write a balanced equation when this oxide is dissolved in water.
(e) Draw the electron dot structure for the formation of this oxide.
(a) The element placed in 2nd Group and 3rd Period of the Periodic Table is Magnesium (Mg).
(b) Electronic configuration: 1s2, 2s2 2p6 3s2
K, L, M
2, 8, 2
(c) When the magnesium metal burns in oxygen, it produces magnesium oxide.
2Mg(s) + O2(g) → 2MgO(s)
When magnesium oxide is heated with water, magnesium hydroxide is formed.
(d) MgO(s) + H2O(l) → Mg(OH)2(aq)
Electron dot structure:

Magnesium loses two electrons and oxygen gains two electrons to complete the octet structure.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.