Q4 of 35 Page 90

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly

Current, I= 1 A


Time, t = 16 seconds


No. of electrons, N = I×T/e



= 1020 electrons

More from this chapter

All 35 →