Q19 of 95 Page 84

The two adjacent sides of a rectangle are 5x2 – 3y2 and x2 + 2xy. Find the perimeter.

We know that;


Two adjacent sides of a rectangle are l and b;


l = 5x2 – 3y2


b = x2 + 2xy


Perimeter of rectangle = (2l+2b)


Which is;


2 (5x2 – 3y2) + 2(x2 + 2xy)


= (10x2 – 6y2) + (2x2 + 4xy)



More from this chapter

All 95 →
17

Subtract:

4p2 + 5q2 – 6r2 + 7 from 3p2 – 4q2 – 5r2 – 6

 18

What must be subtracted from 3a2 – 6ab – 3b2 – 1 to get 4a2 – 7ab – 4ab2 + 1?

 20

The perimeter of triangle is 6p2 – 4p + 9 and two of its sides are p2 – 2p + 1 and 3p2 – 5p + 3. Find the third side of the triangle.

 1

Find each of the following products:

(5x + 7) × (3x + 4)