Q2 of 44 Page 102

In figure, if ∠AOB = 125°, then ∠COD is equal to

As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle.


So, we have


∠AOB + ∠COD = 180°


125° + ∠COD = 180°


∠COD = 55°

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