Q6 of 96 Page 157

For the following distribution,


the sum of lower limits of the median class and modal class is

Here,


Now, N/2 = 66/2 = 33, which lies in the interval 10 - 15. Therefore, lower limit of the median class is 10.


The highest frequency is 20, which lies in the interval 15 - 20. Therefore, lower limit of modal class is 15. Hence, required sum is 10 + 15 = 25.

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