Q18 of 19 Page 510

Write the truth table for circuit given in Fig. 14.47 below consisting of NOR gates and identify the logic operation (OR, AND, NOT) which this circuit is performing.


(Hint: A = 0, B = 1 then A and B inputs of second NOR gate will be 0 and hence Y = 1. Similarly, work out the values of Y for other combinations of A and B. Compare with the truth table of OR, AND, NOT gates and find the correct one.)

The given circuit is as follows:


The first NOR gate gives the output (A + B)’. The second NOR gate gives the output ((A + B)’ + (A + B)’)’.


Using De Morgan’s law,


((A + B)’ + (A + B)’)’ = ((A + B)’)’∙((A + B)’)’ = (A + B)∙(A + B) = A + B (Since, A∙A = A)


So, the output is Y = A + B and the circuit acts as an OR gate.


The truth table for the given circuit is as follows:





























Input (A)



Input (B)



Output (Y)



0



0



0



0



1



1



1



0



1



1



1



1



NOTE: NOR gate is a universal gate because it can be used to implement any Boolean function without using any other gates.


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