Q7 of 20 Page 285

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

Given: Amplitude of magnetic field part of harmonic electromagnetic wave, B0 = 510 nT

Converting into Tesla, B0 = 510 × 10-9 T


Speed of light in vacuum, c = 3 × 108 m/s


Amplitude of the electric field part of the wave can be calculated by the following expression:


E = c B0


E = 3× 108ms-1 ×510 × 10-9 T


⇒ E = 153 N/C


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