For what values of 
Multiplying matrices on the left hand side
L.H.S = 

= [6.0 + 2.2 + 4.x]
= [4 + 4x]
R.H.S = O (O
is the null matrix)
= 0
∴ L.H.S = R.H.S, so we get,
[4+4x] = O
4 + 4x = 0
4x = -4
x = -1
Hence value of x is equal to -1.
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the equation A’A =I.
show that A2 – 5A + 7I =0.