Q4 of 40 Page 371

Using integration find the area of region bounded by the triangle whose vertices are (– 1, 0), (1, 3) and (3, 2).


BL and CM are drawn perpendicular to x – axis.


We can see that from the figure that,


Area(ΔACB) = Area(ALBA) + Area(BLMCA) - Area(AMCA) …(1)


Now, equation of line segment AB is




Thus, Area(ALBA) =



Now, equation of line segment BC is




Thus, Area (BLMCB) =



Now, equation of line segment AC is




Thus, Area (AMCA) =



Now putting all these values in equation (1), we get,


Area(ΔABC) = (3 + 5 – 4) = 4 units.


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