If the vertices A, B, C of a triangle ABC are (1, 2, 3), (–1, 0, 0), (0, 1, 2), respectively, then find ∠ABC, [∠ABC is the angle between the vectors
].
Given points are A (1, 2, 3), B (-1, 0, 0) and C (0, 1, 2)
∠ABC is the angle between vectors ![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
We know
![]()
![]()
![]()
![]()
⇒ ∠ABC = cos-1(10/√102)
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.