A scooter moving at a speed of 10m/s is stopped by applying brakes which produce a uniform acceleration of –0.5m/s2. How much distance will be covered by the scooter before it stops?
Initial speed, u = 10m/s
Final speed, v = 0 (Scooter stops)
Acceleration, a = -0.5m/s2
And, Distance covered, s = ?(To be calculated)
Now, putting these values in the third equation of motion:V2 = u2 + 2as
We get, (0)2 = (10)2 + 2 x (-0.5) x s
0 = 100-s
s = 100m
Thus, the distance covered in 100 metres.
Final speed, v = 0 (Scooter stops)
Acceleration, a = -0.5m/s2
And, Distance covered, s = ?(To be calculated)
Now, putting these values in the third equation of motion:V2 = u2 + 2as
We get, (0)2 = (10)2 + 2 x (-0.5) x s
0 = 100-s
s = 100m
Thus, the distance covered in 100 metres.
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