Q27 of 62 Page 10

In the figure find value of 'x'.
      

 From the given figure,
∠ACB = ∠AOB
       = 󗄠 = 60° 
Now ∠ACB + ∠BCD = 180° 
      Þ 60°  + ∠BCD = 180° 
      Þ 󐯍 = 120°  
Again in the bigger circle,  m () = 2∠BCD 
                                             = 2 ´ 120= 240°  
Now m (  ) + m() = 360° 
⇒ 240°  + x°  = 360°   ⇒ x = 360° - 240°
Þ x = 120°  

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25 AB is a diameter of a circle C(O, r) and radius OD ⊥ AB. If C is any point on arc DB, then find ∠BAD and ∠CAD.
If ∠BAC = 20°, find ∠DAC.  26   AB and AC are two chords of a circle and the diameter passing through 'A' bisects the angle ∠BAC. Prove that AB = AC.
  28 Prove that the line of centers of two intersecting circles subtends equal Angles at the two points of intersection. 29 Two chords AB and CD of lengths 5cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its center. If the distance between AB and CD is 6cm, find the radius of the circle.