A flag-staff stands at the top of a 5 m high tower. From a point on the ground,the angle of elevation of the top of the flag-staff is 60º and from the samepoint, the angle of elevation of the top of the tower is 45º. Find the heightof the flag-staff.
Given:
Height of the tower, h = 5 m
Angle of elevation of the top of the flag staff, θ = 60°
Angle of elevation of top of tower, ϕ = 45 °
To find: Height of the flag staff.
Solution:
Let BC be the height of the tower and DC be the height of the flag-staff.
In right angled Δ ABC,
AB = BC cot 45°
AB = 5 m ………………….(i)
In right angled Δ ABD,
AB = BD cot 60°
AB = (BC + CD) cot 60°
AB = (5 + CD) × ( 1 / √ 3) ………………….(ii)
Equating (i) and (ii)
(5 + CD) × (1 / √ 3) = 5
(5 + CD) = 5 × (√ 3)
CD = (5× √ 3 ) - 5
= 5(1.732 - 1)
= 5 × 0.732
= 3.66 m
Therefore the height of the flag-staff is 3.66 m
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