Q5 of 8 Page 11

Divide a line segment of 7 cm length externally in the ratio of 3 : 5.

Given: AB is a line segment of 7 cm length. Required: To divide a line segment of 7 cm length externally in the ratio of 3 : 5.                Steps of Construction:1. Draw the line segment AB = 7 cm.
2. Draw ray BX making an acute ∠ ABX .3. Along BX, mark off five points B1, , B2, B3, , B4 and B5. Join B2 to A.
4. Through B5 draw B5P || B2A , intersecting BA produced at P.
5. The point P so obtained is the required point which divides AB externally in the ratio
3 : 5.Proof: In Δs ABB2 and PBB5, B5P || B2A ⇒ ABB2 ∼ PBB5∴ =(Property of similarty).⇒

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